0xgame2023复现


misc

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赛博厨子一把梭

最后flag为

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0xGame{Welc0me_To_0xGame2023!!}

重生之我在教学楼打cs

bsp⽂件再结合题⽬名可以搜索到是cs的地图,尝试之后可以⽤GCFScape打开

最后flag为

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0xGame{CS_very_good}

shark shark

ctfnat-A一把梭得到ftp登录密码

ftp追踪流得到压缩包

保存压缩包并解压压缩包得到flag

最后flag为

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0xGame{7a504dab-ada6-4c41-adb3-0d1530098cd4}

hide and seek

steghide隐写弱⼝令爆破,使⽤rockyou.txt

最后flag为

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0xGame{Just_h1de_and_S33k}

least and most

least significant bit和most significant bit
使⽤stegsolve⼯具

最后flag为

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0xGame{lsb_combined_with_msb}

findme2

下载附件

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我们的老朋友WearyMeadow听说0xGame2023开始了,和zysgmzb进行了一手小小的py提前拿到了第二周的所有题目,然后顺手写了Misc部分的wp发到博客里,为了防止上次的情况再次发生,他把github里的密码全删了,这次应该安全了

根据题目描述,直接去github搜索WearyMeadow

可以看到一共两个项目, 一个是博客,另一个是自用的登录脚本

博客里只有一篇上锁的wp

结合题目描述说把密码删了,就可以去翻一翻修改记录

直接解锁文章就可以拿到flag

最后flag为

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0xGame{OHHHH_You_Find_Me_%%%}

Miversc

先用ook和brainfuck之间的对应关系得到原始的brainfuck代码

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>++++++++[>>++>++++>++++++>++++++++>++++++++++>++++++++++++>++++++++++++++>++++++++++++++++>++++++++++++++++++>++++++++++++++++++++>++++++++++++++++++++++>++++++++++++++++++++++++>++++++++++++++++++++++++++>++++++++++++++++++++++++++++>++++++++++++++++++++++++++++++<<<<<<<<<<<<<<<<-]>>>>>++++++++.>>+++++.>----..+++.<<<<----.<.>>>>>+.----.<.----.>+++++++.<++++.<<<<.>>>>++++.+++++.++.>++.-.<<<<<.>>>>>.<--------.---.<<<<.>>>>+.++++++.-----------.++++++.[>]+[[-]<]>,<++++++[->--------<]>,<++++++++++[->------------<]>,-<+++++++[->----------<]>,--<+++++[->-------------------<]>,+<++++++++++[->-----------<]>,-<++++++++++[->----------<]>,---<++++++++++[->------------<]>,+<+++++[->---------------<]>,+++<++++++++++[->------------<]>,<+++++[->-----------------------<]>,<++++[->-----------------------------<]>,<+++++[->-------------------<]>,--<++++++++[->----------<]>,-<++++++++++[->----------<]>,++<++++++++++[->------------<]>,-<++++++++++[->----------<]>,<++++++[->-------------------<]>,<+++++[->-----------------------<]>,-<++++++++++[->----------<]>,<+++++[->-------------------<]>,+<++++++++[->----------<]>,-<++++++++++[->-----------<]>,<+++++[->---------------<]>,<+++[->-----------<]>,<+++++[->-------------------------<]++++++++[>>++>++++>++++++>++++++++>++++++++++>++++++++++++>++++++++++++++>++++++++++++++++>++++++++++++++++++>++++++++++++++++++++>++++++++++++++++++++++>++++++++++++++++++++++++>++++++++++++++++++++++++++>++++++++++++++++++++++++++++>++++++++++++++++++++++++++++++<<<<<<<<<<<<<<<<-]>>>>>>>++++++.>----.<-----.>-----.<<<<<.>>>>>++.++++++++++.<<<<<.>>>>>++++.<+++++++.-------.>---.<<<<<.>>>>>+++++.----------.++++++.<<<<<.>>>>++++++++.+++++.++.>.-.

然后搜索brainfuck基本语法再来看这段代码即可知道只是非常简单的比较,每一轮比较的结果是当前cell和下一个cell都为0

借用大佬exp:

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# msg = open('miverse.txt').read().replace('\n','').replace('\r','')
#
# dic = {'.?':'>',
# '?.':'<',
# '..':'+',
# '!!':'-',
# '!.':'.',
# '.!':',',
# '!?':'[',
# '?!':']'}
# cmd = ''.join([ dic[msg[i:i+2]] for i in range(0, len(msg), 2) ])
# print(cmd)
cmd=open('m3.txt').read()
op = [0]*1000
rip = 0
p = 0
while p<len(cmd):
i = cmd[p]
p += 1
if i == '>':
rip+=1
elif i == '<':
rip-=1
elif i == '+':
op[rip]+=1
elif i == '-':
op[rip]-=1
elif i == '.':
print('==>',chr(op[rip]))
elif i == ',':
op[rip] = ord(input('---->')[0])
elif i == '[':
if op[rip] == 0:
cnt = 1
while cnt != 0:
if cmd[p] == '[': cnt += 1
if cmd[p] == ']': cnt -= 1
p += 1
elif i == ']':
cnt = 1
p -= 1
while cnt!=0:
p -= 1
if cmd[p] == ']' : cnt += 1
if cmd[p] == '[' : cnt -= 1
if p>440:
print(p,rip,op[:25])


#输入字符后运算应等于0
#b'Just_ReLerse_OoK!'

'''
---->o
1116 3 [0, 0, 0, 111, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
...
1145 3 [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
---->k
1146 3 [0, 0, 0, 107, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
...
1173 3 [0, 0, 0, 32, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
---->!
1174 3 [0, 0, 0, 33, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
...
1195 3 [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
'''

最后flag为

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0xGame{Just_ReLerse_OoK!}

crypto

觅码

下载附件

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from secret import flag #从中导入秘密的flag,这是我们要破解的信息
from Crypto.Util.number import bytes_to_long #从函数库导入一些编码函数
from base64 import b64encode

#hint:也许下列函数库会对你有些帮助,但是要怎么用呢……
from base64 import b64decode
from gmpy2 import iroot
from Crypto.Util.number import long_to_bytes

flag = flag.encode()
lent = len(flag)
flag = [flag[i*(lent//4):(i+1)*(lent//4)] for i in range(4)]#将flag切割成四份

c1 = bytes_to_long(flag[0])
c2 = ''.join([str(bin(i))[2:] for i in flag[1]])
c3 = b64encode(flag[2])
c4 = flag[3].hex()
print(f'c1?= {pow(c1,5)}\nc2 = {c2}\nc3 = {c3}\nc4 = {c4}')

'''
c1?= 2607076237872456265701394408859286660368327415582106508683648834772020887801353062171214554351749058553609022833985773083200356284531601339221590756213276590896143894954053902973407638214851164171968630602313844022016135428560081844499356672695981757804756591891049233334352061975924028218309004551
c2 = 10010000100001101110100010100111101000111110010010111010100001101110010010111111101000011110011010000001101011111110011010011000101011111110010110100110100000101110010010111101100101011110011110111100
c3 = b'lueggeeahO+8jOmCo+S5iOW8gOWni+aIkQ=='
c4 = e4bbace79a8443727970746fe68c91e68898e590a72121217d
'''
#全是乱码,那咋办嘛?

分了4段进行加密,part1是转整后再5次幂,part2是转二进制,part3是base64,part4是16进制,最后合起来是乱码bytes转str用utf-8(默认值)

exp:

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from gmpy2 import iroot
from Crypto.Util.number import *
from base64 import b64decode
c1 = 2607076237872456265701394408859286660368327415582106508683648834772020887801353062171214554351749058553609022833985773083200356284531601339221590756213276590896143894954053902973407638214851164171968630602313844022016135428560081844499356672695981757804756591891049233334352061975924028218309004551
c2 = 10010000100001101110100010100111101000111110010010111010100001101110010010111111101000011110011010000001101011111110011010011000101011111110010110100110100000101110010010111101100101011110011110111100
c3 = b'lueggeeahO+8jOmCo+S5iOW8gOWni+aIkQ=='
c4 = 'e4bbace79a8443727970746fe68c91e68898e590a72121217d'

flag = (long_to_bytes(iroot(c1,5)[0])+long_to_bytes(eval('0b'+str(c2)))+b64decode(c3)+long_to_bytes(eval('0x'+str(c4)))).decode()
print(flag)

运行得到

最后flag为

1
0xGame{ 恭喜你,已经理解了信息是如何编码的,那么开始我们的Crypto挑战吧!!!}

BabyRSA

下载附件

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from Crypto.Util.number import *
from random import getrandbits
from secret import flag

def getN():
N = 1
for i in range(16):
tmp = getPrime(32)
N *= tmp
return N

mask = getrandbits(256)
e = 65537
n = getN()
m = bytes_to_long(flag)
c = pow(m*mask,e,n)
print(f'n = {n}')
print(f'e = {e}')
print(f'c = {c}')
print(f'mask = {mask}')


'''
n = 93099494899964317992000886585964221136368777219322402558083737546844067074234332564205970300159140111778084916162471993849233358306940868232157447540597
e = 65537
c = 54352122428332145724828674757308827564883974087400720449151348825082737474080849774814293027988784740602148317713402758353653028988960687525211635107801
mask = 54257528450885974256117108479579183871895740052660152544049844968621224899247
'''

exp:

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from Crypto.Util.number import *
n = 93099494899964317992000886585964221136368777219322402558083737546844067074234332564205970300159140111778084916162471993849233358306940868232157447540597
e = 65537
c = 54352122428332145724828674757308827564883974087400720449151348825082737474080849774814293027988784740602148317713402758353653028988960687525211635107801
mask=54257528450885974256117108479579183871895740052660152544049844968621224899247
fact=[2329990801,2436711469,2732757047,2770441151,2821163021,2864469667,2995527113,3111632101,3162958289,3267547559,3281340371,3479527847,3561068417,3978177241,4134768233,4160088337]
phi = 1
for i in fact:
phi *= i-1
d = inverse(e,phi)
c =pow(c,d,n)
mask_inv=(inverse(mask//GCD(mask,n),n))
c = c*mask_inv%n
m = long_to_bytes(c//GCD(mask,n))
print(m)

运行得到

最后flag为

1
0xGame{Magic_M@th_Make_Crypt0}

Take my bag

下载附件

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from Crypto.Util.number import *

from secret import flag

def encrypt(m):
m = str(bin(m))[2:][::-1]
enc = 0
for i in range(len(m)):
enc += init[i] * int(m[i]) % n
return enc

w = getPrime(64)
n = getPrime(512)
init = [w*pow(3, i) % n for i in range(512)]

c = encrypt(bytes_to_long(flag))

print(f'w={w}')
print(f'n={n}')
print(f'c={c}')

'''
w=16221818045491479713
n=9702074289348763131102174377899883904548584105641045150269763589431293826913348632496775173099776917930517270317586740686008539085898910110442820776001061
c=4795969289572314590787467990865205548430190921556722879891721107719262822789483863742356553249935437004378475661668768893462652103739250038700528111
'''

超递增序列,背包密码

exp:

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from Crypto.Util.number import *

w=16221818045491479713
n=9702074289348763131102174377899883904548584105641045150269763589431293826913348632496775173099776917930517270317586740686008539085898910110442820776001061
c=4795969289572314590787467990865205548430190921556722879891721107719262822789483863742356553249935437004378475661668768893462652103739250038700528111
c = c*inverse(w,n)%n

def decrypt(c):
index = 0
m = 0
while pow(3,index)<c:
index+=1
for i in range(index-1,-1,-1):
if ((pow(3,i+1)>c)&(pow(3,i)<=c)):
c -= pow(3,i)
m += pow(2,i)
return m

print(long_to_bytes(decrypt(c)))

运行得到

最后flag为

1
0xGame{Welc0me_2_Crypt0_G@me!#$&%}

CBC

下载附件

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from Crypto.Util.number import *
from secret import flag,key

def bytes_xor(a,b):
a,b=bytes_to_long(a),bytes_to_long(b)
return long_to_bytes(a^b)

def pad(text):
if len(text)%8:
pad = 8-(len(text)%8)
text += pad.to_bytes(1,'big')*pad
return text
else:
return text

def Encrypt_CBC(text,iv,key):
result = b''
text = pad(text)
block=[text[_*8:(_+1)*8] for _ in range(len(text)//8)]
for i in block:
tmp = bytes_xor(iv,i)
iv = encrypt(tmp,key)
result += iv
return result

def encrypt(text,key):
result = b''
for i in text:
result += ((i^key)).to_bytes(1,'big')
return result

iv = b'11111111'
enc = (Encrypt_CBC(flag,iv,key))
print(f'enc = {enc}')

#enc = b"\x8e\xc6\xf9\xdf\xd3\xdb\xc5\x8e8q\x10f>7.5\x81\xcc\xae\x8d\x82\x8f\x92\xd9o'D6h8.d\xd6\x9a\xfc\xdb\xd3\xd1\x97\x96Q\x1d{\\TV\x10\x11"

穷举爆破

exp:

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from Crypto.Util.number import *

def bytes_xor(a,b):
a,b=bytes_to_long(a),bytes_to_long(b)
return long_to_bytes(a^b)

def decrypt(text,key):
result = b''
for i in text:
result += ((i^key)).to_bytes(1,'big')
return result

def CBCinv(enc,iv,key):
result = b''
block=[enc[_*8:(_+1)*8] for _ in range(len(enc)//8)]
for i in block:
temp = decrypt(i,key)
tmp = bytes_xor(iv,temp)
iv = i
result += tmp
return result

iv = b'11111111'
enc = enc = b"\x8e\xc6\xf9\xdf\xd3\xdb\xc5\x8e8q\x10f>7.5\x81\xcc\xae\x8d\x82\x8f\x92\xd9o'D6h8.d\xd6\x9a\xfc\xdb\xd3\xd1\x97\x96Q\x1d{\\TV\x10\x11"
for key in range(0xff):
dec = (CBCinv(enc,iv,key))
if b'0xGame' in dec:
print(dec)

运行得到

最后flag为

1
0xGame{098f6bcd4621d373cade4e832627b4f6}

猜谜

下载附件

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from secret import flag,key
from Crypto.Util.number import *

def dec(text):
text = text.decode()
code = 'AP3IXYxn4DmwqOlT0Q/JbKFecN8isvE6gWrto+yf7M5d2pjBuk1Hh9aCRZGUVzLS'
unpad = 0
tmp = ''
if (text[-1] == '=') & (text[-2:] != '=='):
text = text[:-1]
unpad = -1
if text[-2:] == '==':
text = text[:-2]
unpad = -2
for i in text:
tmp += str(bin(code.index(i)))[2:].zfill(3)
tmp = tmp[:unpad]
result = long_to_bytes(int(tmp,2))
return result

def enc(text):
code = 'AP3IXYxn4DmwqOlT0Q/JbKFecN8isvE6gWrto+yf7M5d2pjBuk1Hh9aCRZGUVzLS'
text = ''.join([str(bin(i))[2:].zfill(8) for i in text])
length = len(text)
pad = b''
if length%3 == 1:
text += '00'
pad = b'=='
elif length%3 == 2:
text += '0'
pad = b'='
result = [code[int(text[3*i:3*(i+1)],2)] for i in range(0,len(text)//3)]
return ''.join(result).encode()+pad

def encrypt(flag):
result = b''
for i in range(len(flag)):
result += (key[i%7]^(flag[i]+i)).to_bytes(1,'big')
return result


c = enc(encrypt(flag))
print(f'c = {c}')

'''
c = b'IPxYIYPYXPAn3nXX3IXA3YIAPn3xAYnYnPIIPAYYIA3nxxInXAYnIPAIxnXYYYIXIIPAXn3XYXIYAA3AXnx='
'''

侧信道攻击

exp:

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from Crypto.Util.number import *

def dec(text):
text = text.decode()
code = 'AP3IXYxn4DmwqOlT0Q/JbKFecN8isvE6gWrto+yf7M5d2pjBuk1Hh9aCRZGUVzLS'
unpad = 0
tmp = ''
if (text[-1] == '=') & (text[-2:] != '=='):
text = text[:-1]
unpad = -1
if text[-2:] == '==':
text = text[:-2]
unpad = -2
for i in text:
tmp += str(bin(code.index(i)))[2:].zfill(3)
tmp = tmp[:unpad]
result = long_to_bytes(int(tmp,2))
return result

c = b'IPxYIYPYXPAn3nXX3IXA3YIAPn3xAYnYnPIIPAYYIA3nxxInXAYnIPAIxnXYYYIXIIPAXn3XYXIYAA3AXnx='
enc = dec(c)

mask = b''
kown = b'0xGame{'
for i in range(7):
mask += (enc[i]^(kown[i]+i)).to_bytes(1,'big')
flag = b''
for i in range(len(enc)):
flag +=((mask[i%7]^enc[i])-i).to_bytes(1,'big')
print(flag)

运行得到

最后flag为

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0xGame{Kn0wn_pl@intext_Att@ck!}

维吉尼亚密码

下载附件

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0dGmqk{79ap4i0522g0a67m6i196he52357q60f}

维吉尼亚根据flag格式推算密钥得到game

最后flag为

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0xGame{79ad4e0522a0a67a6e196be52357e60b}

中间的那个人

下载附件

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from secret import flag
from Crypto.Util.number import *
from Crypto.Cipher import AES
from hashlib import sha256
from random import *

p = getPrime(128)
g = 2
A = getrandbits(32)
B = getrandbits(32)

Alice = pow(g,A,p)
Bob = pow(g,B,p)
key = pow(Alice,B,p)
key = sha256(long_to_bytes(key)).digest()

iv = b"0xGame0xGameGAME"
aes = AES.new(key, AES.MODE_CBC, iv)
enc = aes.encrypt(flag)
print(f'g={g}\np={p}') #we tell
print(f'Bob={Bob}') #Bob tell
print(f'Alice={Alice}') #Alice tell

print(f'enc={enc}')#Here is they secret

'''
g=2
p=250858685680234165065801734515633434653
Bob=33067794433420687511728239091450927373
Alice=235866450680721760403251513646370485539
enc=b's\x04\xbc\x8bT6\x846\xd9\xd6\x83 y\xaah\xde@\xc9\x17\xdc\x04v\x18\xef\xcf\xef\xc5\xfd|\x0e\xca\n\xbd#\x94{\x8e[.\xe8\xe1GU\xfa?\xda\x11w'
'''

DH算法

exp:

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from Crypto.Util.number import *
from Crypto.Cipher import AES
from hashlib import sha256
g=2
p=250858685680234165065801734515633434653
Bob=33067794433420687511728239091450927373
Alice=235866450680721760403251513646370485539

x = 3992780394
key = pow(Bob,x,p)
key = sha256(long_to_bytes(key)).digest()
iv = b"0xGame0xGameGAME"
aes = AES.new(key, AES.MODE_CBC, iv)
enc=b's\x04\xbc\x8bT6\x846\xd9\xd6\x83 y\xaah\xde@\xc9\x17\xdc\x04v\x18\xef\xcf\xef\xc5\xfd|\x0e\xca\n\xbd#\x94{\x8e[.\xe8\xe1GU\xfa?\xda\x11w'

flag = aes.decrypt(enc)
print(flag)

运行得到

最后flag为

1
0xGame{51393fe1fd5fc2df1bf018d06f0fa11d}

What’s CRT?

下载附件

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from Crypto.Util.number import *
from secert import flag

m = bytes_to_long(flag)
e = 260792700
q,p,q_,p_ = [getPrime(512) for _ in range(4)]
gift = [q+p,q_+p_]
n,n_ = q*p,q_*p_
mq_ = pow(m,4,q_)
mp_ = pow(m,4,p_)
c = pow(m,e,n)

print(f'mygift={gift}\nmq_={mq_}\nmp_={mp_}\nn={n}\nn_={n_}\nc={c}')
'''
mygift=[15925416640901708561793293991573474917595642805739825596593339102414328214313430010166125066639132916608736569443045051644173933089503934675628814467277922, 18342424676996843423829480445042578097182127446865571536445030052846412665700132683433441858073625594933132038175200824257774638419166516796318527302903098]
mq_=6229615098788722664392369146712291169948485951371133086154028832805750551655072946170332335458186479565263371985534601035559229403357396564568667218817197
mp_=7514598449361191486799480225087938913945061715845128006069296876457814528347371315493644046029376830166983645570092100320566196227210502897068206073043718
n=63329068473206068067147844002844348796575899624395867391964805451897110448983910133293450006821779608031734813916287079551030950968978400757306879502402868643716591624454744334316879241573399993026873598478532467624301968439714860262264449471888606538913071413634346381428901358109273203087030763779091664797
n_=84078907800136966150486965612788894868587998005459927216462899940718213455112139441858657865215211843183780436155474431592540465189966648565764225210091190218976417210291521208716206733270743675534820816685370480170120230334766919110311980614082807421812749491464201740954627794429460268010183163151688591417
c=12623780002384219022772693100787925315981488689172490837413686188416255911213044332780064192900824150269364486747430892667624289724721692959334462348218416297309304391635919115701692314532111050955120844126517392040880404049818026059951326039894605004852370344012563287210613795011783419126458214779488303552
'''

exp:

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import gmpy2
from Crypto.Util.number import *
p_=8991690869897246321907509983425307437365288417861457732721314572165773880898701105065818281248373676758405021157703190132511219384704650086565345885727777
q_=9350733807099597101921970461617270659816839029004113803723715480680638784801431578367623576825251918174727017017497634125263419034461866709753181417175321
q = 7687653192574283689842465763299611592007909813801176843577189341409409692975753037402253496632410364594655611337156337669083582400443042348458268161331043
p = 8237763448327424871950828228273863325587732991938648753016149761004918521337676972763871570006722552014080958105888713975090350689060892327170546305946879
e = 260792700
mygift=[15925416640901708561793293991573474917595642805739825596593339102414328214313430010166125066639132916608736569443045051644173933089503934675628814467277922, 18342424676996843423829480445042578097182127446865571536445030052846412665700132683433441858073625594933132038175200824257774638419166516796318527302903098]
mq_=6229615098788722664392369146712291169948485951371133086154028832805750551655072946170332335458186479565263371985534601035559229403357396564568667218817197
mp_=7514598449361191486799480225087938913945061715845128006069296876457814528347371315493644046029376830166983645570092100320566196227210502897068206073043718
n=63329068473206068067147844002844348796575899624395867391964805451897110448983910133293450006821779608031734813916287079551030950968978400757306879502402868643716591624454744334316879241573399993026873598478532467624301968439714860262264449471888606538913071413634346381428901358109273203087030763779091664797
n_=84078907800136966150486965612788894868587998005459927216462899940718213455112139441858657865215211843183780436155474431592540465189966648565764225210091190218976417210291521208716206733270743675534820816685370480170120230334766919110311980614082807421812749491464201740954627794429460268010183163151688591417
c=12623780002384219022772693100787925315981488689172490837413686188416255911213044332780064192900824150269364486747430892667624289724721692959334462348218416297309304391635919115701692314532111050955120844126517392040880404049818026059951326039894605004852370344012563287210613795011783419126458214779488303552
def CRT(r,d):
M = 1
l = len(r)
for i in range(0,l):
M = d[i] * M
x = 0
for i in range(0,l):
md = M//d[i]
x = (x + gmpy2.invert(md, d[i]) * md *r[i] )%M
return int(M+x% M)%M

phi = (q-1)*(p-1)
d = gmpy2.invert(e//4,phi)
m2 = pow(c,d,n)
mq = m2%q
mp = m2%p

m = CRT([mq,mp,mq_,mp_],[q,p,q_,p_])
m = (gmpy2.iroot(m,4))[0]
print(long_to_bytes(m))

运行得到

最后flag为

1
0xGame{7881ed67088e9f72b860f8c376599785}

EzLFSR

下载附件

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from Crypto.Util.number import *
from secret import flag,secret

assert flag == b'0xGame{'+secret+b'}'

def make_mask(m):
tmp = str(bin(bytes_to_long(m)))[2:].zfill(128)
return tmp

def string2bits(s):
return [int(b) for b in s]

def bits2string(bs):
s = [str(b) for b in bs]
return ''.join(s)

def lfsr(state, mask):
assert(len(state) == 128)
assert(len(mask) == 128)

output = 0
for i in range(128):
output = output ^ (state[i] & mask[i])

return output

if __name__ == '__main__':
initState = [0, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 1, 0, 1, 0, 0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 0, 1, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0]
secret = make_mask(secret)
mask = string2bits(secret)

for b in secret: assert(b == '0' or b == '1')
assert(len(secret) == 128)

for i in range(256):
state = initState[i:]
output = lfsr(state, mask)
initState += [output]

outputState = bits2string(initState[128:])
print('outputState =', outputState)

'''
outputState = 1101111111011101100001000011111101001000111000110100010011110111010011100110100100111001101010110110101110000011110101000110010010000011111111001111000110111001100111101110010100100001101001111110001010000100111101011011100010000000100000100000100111010110
'''

线性反馈移位寄存器

exp:

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from Crypto.Util.number import *
def string2bits(s):
return [int(b) for b in s]

initState = [0, 1, 0, 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 1, 0, 1, 0, 0, 1, 1, 1, 1, 0, 0, 1, 1, 1, 1, 0, 1, 0, 1, 1, 0, 1, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0]
outputState = string2bits('1101111111011101100001000011111101001000111000110100010011110111010011100110100100111001101010110110101110000011110101000110010010000011111111001111000110111001100111101110010100100001101001111110001010000100111101011011100010000000100000100000100111010110')
states = initState + outputState

ms = MatrixSpace(GF(2), 128, 128)
mv = []
for i in range(128):
mv += states[i : i + 128]
m= ms(mv)

vs = MatrixSpace(GF(2), 128, 1)
vv = outputState[0:128]
v = vs(vv)

secret = m.inverse() * v
M=secret.str().replace('\n','').replace('[','').replace(']','')
print(long_to_bytes(eval('0b'+M)))

运行得到

最后flag为

1
0xGame{Rec0ver_the_M@sk}

ECC

下载附件

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from Crypto.Util.number import *

def add(P,Q):
if P[0] != Q[0] and P[1] != Q[1]:
t = ((Q[1]-P[1]) * inverse(Q[0]-P[0],q)) %q
else:
t = ((3*P[0]*P[0]+a) * inverse(2*P[1],q))%q

x3 = t*t - P[0] - Q[0]
y3 = t*(P[0] - x3) - P[1]
return (x3%q, y3%q)

def mul(t, A, B=0):
if not t: return B
return mul(t//2, add(A,A), B if not t&1 else add(B,A) if B else A)


q=1139075593950729137191297
a=930515656721155210883162
b=631258792856205568553568

G = (641322496020493855620384, 437819621961768591577606)
K = (781988559490437792081406, 76709224526706154630278)
C_1=(926699948475842085692652, 598672291835744938490461)
C_2=(919875062299924962858230, 227616977409545353942469)
k = 12515237792257199894
tmp = mul(k,C_2)
tmp = (tmp[0],-tmp[1])
M = add(C_1,tmp)


print(long_to_bytes(M[0])+long_to_bytes(M[1]))

exp:

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#part1:求私钥
q=1139075593950729137191297
a=930515656721155210883162
b=631258792856205568553568

G = (641322496020493855620384, 437819621961768591577606)
K = (781988559490437792081406, 76709224526706154630278)
E = EllipticCurve(GF(q),[0,0,0,a,b])
G = E.point(G)
K = E.point(K)
print(G.discrete_log(K))
#12515237792257199894
#part2:解密
from Crypto.Util.number import *
def add(P,Q):
if P[0] != Q[0] and P[1] != Q[1]:
t = ((Q[1]-P[1]) * inverse(Q[0]-P[0],q)) %q
else:
t = ((3*P[0]*P[0]+a) * inverse(2*P[1],q))%q

x3 = t*t - P[0] - Q[0]
y3 = t*(P[0] - x3) - P[1]
return (x3%q, y3%q)

def mul(t, A, B=0):
if not t: return B
return mul(t//2, add(A,A), B if not t&1 else add(B,A) if B else A)


q=1139075593950729137191297
a=930515656721155210883162
b=631258792856205568553568

G = (641322496020493855620384, 437819621961768591577606)
K = (781988559490437792081406, 76709224526706154630278)
C_1=(926699948475842085692652, 598672291835744938490461)
C_2=(919875062299924962858230, 227616977409545353942469)
k = 12515237792257199894
tmp = mul(k,C_2)
tmp = (tmp[0],-tmp[1])
M = add(C_1,tmp)


print(long_to_bytes(M[0])+long_to_bytes(M[1]))

运行得到

最后flag为

1
0xGame{Al1ce_L0ve_B0b}

LLL-FirstBlood

下载附件

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from random import randrange
from Crypto.Util.number import getPrime,bytes_to_long
from secret import flag
assert len(flag) % 4 == 0

length = len(flag)//4
m = [bytes_to_long(flag[i*length:(i+1)*length]) for i in range(4)]
p = getPrime(int(128))

def MakeMask(n,p):
upper = identity_matrix(n)
low = identity_matrix(n)
for i in range(n-1):
for j in range(i+1, n):
upper[i, j] = randrange(1, p)
low[j, i] = randrange(1, p)
result = upper * low
assert det(result) == 1
return result

def Matrix2List(x):return [list(i) for i in x]

noise = [[randrange(1, p) for i in range(4)] for _ in range(4)]
noise[0] = m
M = matrix(noise)
A = MakeMask(4,p)
C = A*M

print(f'p={p}')
print(f'C={Matrix2List(C)}')
'''
p=198880159035681668071031460916089145469
C=[[1528140902799730745476264672501768332416990282355490479242339131918301176698899635154781328839496210200676497333428, 2081687444435007467807250373278513114045272585243815458840083487459795021302180077490134099644993120009567147202772, 3080873409460299046339495750746632185307246572817534784703936044874106809413620470006445984962733721029566440253675, 3491734341995174183626991907292607070252197520631412767989879432598743851171175369180080355977574296558734415823458], [2359409535809048127331244699867147546817134802610067329431135227991488324148374065940238308147500809599395748756798, 3191196199160821446351036460385791985682645040446022512790815348810555748825420237291839170774872264097466183208742, 4665346530155386457242345394284286198347336281451530670818113876767736288089400119492317775648206643242839430899283, 5369350746042850276067380638571565496087948799720968959426256192923852197959381101839484196445995828389461004495917], [1641407111066265429602929560264443103285908072677065498760570514577412905392260182334706635555256537745902283191251, 2190536173399177167068153351271988931232272884028569669242062395087922275021628334797729266560930040116807133977244, 3127556759140845426132305699421707182108351516931881411928719802847628408656887897596425133523782526561471050447359, 3707239956529200159380870618471703921011276020439315706352183576289925263316580408968092016782483770373121972835410], [9883814543195849013523934427451407019514807606993414569626142656857168165339, 13190422499129347541373922929251088892868361241120937213742340947017395215646, 18832738552342488056498211782604832513006649329982003661701684946590064734701, 22323329751908690611034666068697427811613727429398087082295754189068333861152]]
'''

exp:

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from Crypto.Util.number import *
C=[[1528140902799730745476264672501768332416990282355490479242339131918301176698899635154781328839496210200676497333428, 2081687444435007467807250373278513114045272585243815458840083487459795021302180077490134099644993120009567147202772, 3080873409460299046339495750746632185307246572817534784703936044874106809413620470006445984962733721029566440253675, 3491734341995174183626991907292607070252197520631412767989879432598743851171175369180080355977574296558734415823458], [2359409535809048127331244699867147546817134802610067329431135227991488324148374065940238308147500809599395748756798, 3191196199160821446351036460385791985682645040446022512790815348810555748825420237291839170774872264097466183208742, 4665346530155386457242345394284286198347336281451530670818113876767736288089400119492317775648206643242839430899283, 5369350746042850276067380638571565496087948799720968959426256192923852197959381101839484196445995828389461004495917], [1641407111066265429602929560264443103285908072677065498760570514577412905392260182334706635555256537745902283191251, 2190536173399177167068153351271988931232272884028569669242062395087922275021628334797729266560930040116807133977244, 3127556759140845426132305699421707182108351516931881411928719802847628408656887897596425133523782526561471050447359, 3707239956529200159380870618471703921011276020439315706352183576289925263316580408968092016782483770373121972835410], [9883814543195849013523934427451407019514807606993414569626142656857168165339, 13190422499129347541373922929251088892868361241120937213742340947017395215646, 18832738552342488056498211782604832513006649329982003661701684946590064734701, 22323329751908690611034666068697427811613727429398087082295754189068333861152]]
C = Matrix(ZZ,C).LLL()
flag = b''
for i in list(C[0]):
flag +=(long_to_bytes(-i))
print(flag)

运行得到

最后flag为

1
0xGame{8e4d5924dc4cd78f11c1eeb99e991ab3}

LLL-SecondBlood

下载附件

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from Crypto.Util.number import *
from secret import flag

m = bytes_to_long(flag)
q = getPrime(512)
assert m.bit_length() == 318

def encrypt(m):
mask,noise = getPrime(511),getPrime(50)
mask_.append(mask)
noise_.append(noise)
c = (mask*m + noise)%q
return c

noise_,mask_ =[[] for _ in range(2)]
c_ = [encrypt(m) for i in range(4)]

print(f'q = {q}\nmask = {mask_}\nc_ = {c_}')

'''
q = 9342426601783650861020119568565656404715236059903009041977149778244153930435908024696666887269890479558473622355346816236972767736577737332173213722012253
mask = [6237128445236992920577225644858662677575951126467888858782461334057970069468925833844231116647406833999142659751374620280213290736114576089069396331226747, 6368031389213953889417545256750169233725975229197446803885029159767701479445576860704561593200907482372690851152126782391126462547524526631934408981070841, 5106473460982791188578285397420642137630347289252852045044021197988607082777231839839730169682158507822078412449827976663385282021916120837408192506341443, 6318090842950331228033349517542810123596316850353637421587264886413877142612686177796023049304908696413386218992511112752788640732410845589679820003047667]
c_ = [3823539664720029027586933152478492780438595004453489251844133830947165342839393878831914879334660250621422877333022321117120398528430519794109624186204492, 1721659645750224819953244995460589691120672649732560768435214608167861246790136217219349234604724148039910656573436663379375048145045443527267790379816425, 668633520079344839648950502380059311916108468801009386138810324259146523323704014491547148973835774917331333581475920804677395949854411894556705238578896, 497860586379981076499130281851986010889356253371192266267220334713415782402939318483926418213877341511996918189750595755372560345085899109305344338944066]
'''

exp:

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from Crypto.Util.number import *
q = 9342426601783650861020119568565656404715236059903009041977149778244153930435908024696666887269890479558473622355346816236972767736577737332173213722012253
mask = [6237128445236992920577225644858662677575951126467888858782461334057970069468925833844231116647406833999142659751374620280213290736114576089069396331226747, 6368031389213953889417545256750169233725975229197446803885029159767701479445576860704561593200907482372690851152126782391126462547524526631934408981070841, 5106473460982791188578285397420642137630347289252852045044021197988607082777231839839730169682158507822078412449827976663385282021916120837408192506341443, 6318090842950331228033349517542810123596316850353637421587264886413877142612686177796023049304908696413386218992511112752788640732410845589679820003047667]
c_ = [3823539664720029027586933152478492780438595004453489251844133830947165342839393878831914879334660250621422877333022321117120398528430519794109624186204492, 1721659645750224819953244995460589691120672649732560768435214608167861246790136217219349234604724148039910656573436663379375048145045443527267790379816425, 668633520079344839648950502380059311916108468801009386138810324259146523323704014491547148973835774917331333581475920804677395949854411894556705238578896, 497860586379981076499130281851986010889356253371192266267220334713415782402939318483926418213877341511996918189750595755372560345085899109305344338944066]

c = [i for i in c_]
mask.append(1)
mask.append(0)
tmp = [[0 for i in range(len(c)+2)] for _ in range(len(c))]
tmp.append(mask)

for i in range(len(c)):
tmp[i][i]=q
c.append(0)
c.append(pow(2,341))
tmp.append(c)

tmp =matrix(ZZ,tmp)
tmp = tmp.LLL()
print(long_to_bytes(-tmp[0][4]))

运行得到

最后flag为

1
0xGame{19255b5c7b19c790e28d87c8a8bb1d33}

Matrix

下载附件

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from Crypto.Util.number import getPrime
from random import randint
from secert import secert,flag
from hashlib import md5
def n2b(n):return md5(str(n).encode()).hexdigest()

assert secert < pow(2,64)
assert flag == '0xGame{'+n2b(secert)+'}'

def Martix2list(Martix):
result = []
Martix = list(Martix)
for i in Martix:
result.append(list(i))
return result

A=[[12143520799533590286, 1517884368, 12143520745929978443, 796545089340, 12143514553710344843, 28963398496032, 12143436449354407235, 158437186324560, 12143329129091084963, 144214939188320, 12143459416553205779, 11289521392968],[12143520799533124067, 1552775781, 12143520745442171123, 796372987410, 12143514596803995443, 28617862048776, 12143437786643111987, 155426784993480, 12143333265382547123, 140792203111560, 12143460985399172467, 10983300063372],[12143520799533026603, 1545759072, 12143520746151921286, 781222462020, 12143514741528175043, 27856210942560, 12143440210529480891, 150563969013744, 12143339455702534403, 135941365971840, 12143463119774571623, 10579745342712],[4857408319806885466, 2428704161425648657, 12143520747462241175, 758851601758, 12143514933292307603, 7286139389566980165, 9714738936567334300, 144947557513044, 12143346444338047691, 130561054163540, 4857352974113333366, 2428714303424782417],[12143520799533339320, 1476842796, 12143520749060275613, 733281428880, 12143515144091549812, 25896324662208, 12143446129977471347, 139126289668080, 12143353609086952433, 125093278125816, 12143467808884068695, 9705993135696],[3469577371288079926, 5204366058378782250, 12143520750775862343, 706665985740, 12143515359139397843, 24876891455539, 12143449149385190675, 5204499435641729607, 1734628523990131469, 119757210113970, 12143470097256549947, 9282407958928],[10986995009101166671, 1734788687033207505, 12143520752514668698, 680173911560, 12143515570582515443, 23883386182656, 12143452072344092516, 10408859957710764174, 8673790006740000925, 4047954924507284041, 12143472277719610437, 8879790035168],[12143520799534210329, 8095680534365818753, 12143520754224346525, 6071761054204856029, 12143515774342357443, 22931775530664, 12143454859049102627, 122586336122081, 12143373761302849103, 109840689548590, 8095634066844843878, 8500892291801],[2428704159899526175, 7286112481016467893, 12143520755876491019, 629765964828, 12143515968446948123, 9714838668887734012, 4857345013259425502, 117630592711632, 12143379764863568374, 105318302849760, 2428659620509049335, 7286120625945355053],[7286112479717322389, 7286112480971640825, 12143520757456628435, 606320684970, 12143516152115449139, 4857429497934652454, 4857347490735050126, 112978994964264, 12143385390297217523, 101086824360217, 7286069740980100293, 7286120294834973633],[7727695054246476847, 1202487728, 12143520758958480293, 584144077140, 12143516325240923843, 20377952745696, 12143462294760579275, 108622249048560, 12143390651947217363, 97133513961120, 12143479741445599772, 8831658996900830432],[12143520799535388887, 1161628182, 12143520760380594623, 563225247585, 12143516488091679443, 19626876325056, 12143464472820678035, 104545135017180, 12143395570399006523, 93441517429260, 12143481309754543787, 7218375794633]]# 12*12
p = 12143520799543738643
A = Matrix(GF(p),A)
enc = A**secert

def Martix2list(Martix):
result = []
Martix = list(Martix)
for i in Martix:
result.append(list(i))
return result

with open('enc.txt','w') as f:
f.write(str(Martix2list(enc)))

exp:

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A=[[12143520799533590286, 1517884368, 12143520745929978443, 796545089340, 12143514553710344843, 28963398496032, 12143436449354407235, 158437186324560, 12143329129091084963, 144214939188320, 12143459416553205779, 11289521392968],[12143520799533124067, 1552775781, 12143520745442171123, 796372987410, 12143514596803995443, 28617862048776, 12143437786643111987, 155426784993480, 12143333265382547123, 140792203111560, 12143460985399172467, 10983300063372],[12143520799533026603, 1545759072, 12143520746151921286, 781222462020, 12143514741528175043, 27856210942560, 12143440210529480891, 150563969013744, 12143339455702534403, 135941365971840, 12143463119774571623, 10579745342712],[4857408319806885466, 2428704161425648657, 12143520747462241175, 758851601758, 12143514933292307603, 7286139389566980165, 9714738936567334300, 144947557513044, 12143346444338047691, 130561054163540, 4857352974113333366, 2428714303424782417],[12143520799533339320, 1476842796, 12143520749060275613, 733281428880, 12143515144091549812, 25896324662208, 12143446129977471347, 139126289668080, 12143353609086952433, 125093278125816, 12143467808884068695, 9705993135696],[3469577371288079926, 5204366058378782250, 12143520750775862343, 706665985740, 12143515359139397843, 24876891455539, 12143449149385190675, 5204499435641729607, 1734628523990131469, 119757210113970, 12143470097256549947, 9282407958928],[10986995009101166671, 1734788687033207505, 12143520752514668698, 680173911560, 12143515570582515443, 23883386182656, 12143452072344092516, 10408859957710764174, 8673790006740000925, 4047954924507284041, 12143472277719610437, 8879790035168],[12143520799534210329, 8095680534365818753, 12143520754224346525, 6071761054204856029, 12143515774342357443, 22931775530664, 12143454859049102627, 122586336122081, 12143373761302849103, 109840689548590, 8095634066844843878, 8500892291801],[2428704159899526175, 7286112481016467893, 12143520755876491019, 629765964828, 12143515968446948123, 9714838668887734012, 4857345013259425502, 117630592711632, 12143379764863568374, 105318302849760, 2428659620509049335, 7286120625945355053],[7286112479717322389, 7286112480971640825, 12143520757456628435, 606320684970, 12143516152115449139, 4857429497934652454, 4857347490735050126, 112978994964264, 12143385390297217523, 101086824360217, 7286069740980100293, 7286120294834973633],[7727695054246476847, 1202487728, 12143520758958480293, 584144077140, 12143516325240923843, 20377952745696, 12143462294760579275, 108622249048560, 12143390651947217363, 97133513961120, 12143479741445599772, 8831658996900830432],[12143520799535388887, 1161628182, 12143520760380594623, 563225247585, 12143516488091679443, 19626876325056, 12143464472820678035, 104545135017180, 12143395570399006523, 93441517429260, 12143481309754543787, 7218375794633]]
enc=[[11285847990515095003, 7585413350741918021, 11658254512436412666, 477577914899276103, 2941386515764607825, 11283325421744133699, 4096971712575507616, 8118672870538606033, 2377937081025778041, 6576171711896495163, 6152554374963853172, 5022013484610428974], [8354008012616001452, 7787447107046065118, 9504997911333967278, 1082773427768571094, 6015520658629219637, 11244285744740006951, 4493944053220750368, 3504246247470690014, 1738582001618280397, 2330057776906622572, 3043456814665571080, 2981613454022714952], [2508674373714509177, 3544963739532775937, 7952732753025175616, 11161786730565526285, 3397123486689639675, 6454135592624912854, 6613201018024296927, 9748485344986779929, 1819761609989340766, 1259944825407465767, 1596049024644778041, 7769939905324967788], [4200851163596876950, 11960539098651202761, 3303721151143544462, 2532304102428121556, 11083895221097319129, 1171933471304558017, 1549099593543874478, 6088238862927163233, 6459553630361959801, 947358195425767572, 2090533922210134578, 9023030120605201052], [2271102089902208138, 1614812525306266829, 1546249462332047661, 3168333397191737100, 7678980468150522028, 3128939172985153696, 1146041044751755224, 11870173227065140617, 8351303466095252790, 694704483676649448, 7944218023016968278, 583421745603756386], [10309472503110333289, 1100598261990718822, 10235859400888405310, 910925705831020921, 10771855884237562064, 9970830255165655653, 11678899608458971536, 4368822164222204233, 3104861419162339779, 4540709628196554222, 7851809145727500968, 12086896840826708824], [10973051751637593366, 5039073157846327641, 4855314857834773443, 4416954195828423951, 8243966437000815560, 8250554263390748131, 8093181066366682440, 1145520354143718292, 294729013023637045, 10115389386419597159, 2767140395261835843, 6724257139233017485], [6878768250003631244, 10834164422364241529, 6946589221005878489, 539734218479521833, 2691724062063066048, 3989403041446358401, 815244541494093987, 11168528286389981272, 2021358468726921955, 1123433019094267521, 524639025046508882, 5720273332497702547], [6688451244183880831, 10892730373179989558, 6987453292894341174, 5572212176769878684, 11332149024403380575, 3944612864568504791, 6768594304071589280, 10526434024562201079, 10241323610053039912, 1120473558410865753, 306153635148226248, 3606666063074222104], [7556871914690327290, 11353594909211427742, 747771112781361153, 1245068803956910299, 2831489557155431404, 1800035620948876551, 1050411779595241927, 5665981688041778089, 2028968510484240787, 4386552235402890530, 10334391443650474796, 3883841302951550608], [4485787817401669404, 184501191500952934, 3690661645276970957, 6263309802498749034, 6484490370652685031, 9743108369653588026, 3045941510087387269, 5870433915209047275, 4679598273992216016, 11839352681285251516, 4957980185504231911, 7925596893607015470], [1000449712878466719, 7022601702937838844, 1095849907482791166, 11989051568709522226, 6768031250066783733, 185945517026191241, 4280928696740160411, 5633542561098902406, 10176177574499086410, 5782837249861240943, 7406530879613861823, 1971858224839520916]]
p=12143520799543738643
A = matrix(GF(p), A)
enc = matrix(GF(p), enc)
B,P = A.eigenmatrix_right()
P_inv = P.inverse()
assert P*B*P_inv == A
B_=((P_inv*enc*P)[0])[0]
b=(B[0])[0]
x=discrete_log(mod(B_,p),mod(b,p))
print(x)

运行得到

md5加密

1
06450201eb6171d40151563d967e59ea

最后flag为

1
0xGame{06450201eb6171d40151563d967e59ea}

Normal ECC

下载附件

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from Crypto.Util.number import getPrime
from Crypto.Cipher import AES
from random import getrandbits
from hashlib import md5
from secret import flag,M

def MD5(m):return md5(str(m).encode()).hexdigest()
assert '0xGame{'+MD5(M[0])+'}' == flag
p = 11093300438765357787693823122068501933326829181518693650897090781749379503427651954028543076247583697669597230934286751428880673539155279232304301123931419
a = 490963434153515882934487973185142842357175523008183292296815140698999054658777820556076794490414610737654365807063916602037816955706321036900113929329671
b = 7668542654793784988436499086739239442915170287346121645884096222948338279165302213440060079141960679678526016348025029558335977042712382611197995002316466
assert p>a
assert p>b
E = EllipticCurve(GF(p),[a,b])
assert E.order() == p
M = E(M)

G = E.random_point()
k = getPrime(int(128))
K = k*G
r = getrandbits(64)

C1 = M + r*K
C2 = r*G

print(f'p={p}\na={a}\nb={b}')
print(f'G={G.xy()}')
print(f'K={K.xy()}')
print(f'C1={C1.xy()}')
print(f'C2={C2.xy()}')

'''
p=11093300438765357787693823122068501933326829181518693650897090781749379503427651954028543076247583697669597230934286751428880673539155279232304301123931419
a=490963434153515882934487973185142842357175523008183292296815140698999054658777820556076794490414610737654365807063916602037816955706321036900113929329671
b=7668542654793784988436499086739239442915170287346121645884096222948338279165302213440060079141960679678526016348025029558335977042712382611197995002316466
G=(4045939664332192284605924284905750194599514115248885617006435833400516258314135019849306107002566248677228498859069119557284134574413164612914441502516162, 2847794627838984866808853730797794758944159239755903652092146137932959816137006954045318821531984715562135134681256836794735388745354065994745661832926404)
K=(9857925495630886472871072848615069766635115253576843197716242339068269151167072057478472997523547299286363591371734837904400286993818976404285783613138603, 9981865329938877904579306200429599690480093951555010258809210740458120586507638100468722807717390033784290215217185921690103757911870933497240578867679716)
C1=(4349662787973529188741615503085571493571434812105745603868205005885464592782536198234863020839759214118594741734453731681116610298272107088387481605173124, 10835708302355425798729392993451337162773253000440566333611610633234929294159743316615308778168947697567386109223430056006489876900001115634567822674333770)
C2=(5193866657417498376737132473732737330916570240569047910293144235752602489388092937375844109374780050061859498276712695321973801207620914447727053101524592, 684299154840371832195648774293174908478389728255128448106858267664482339440737099810868633906297465450436417091302739473407943955874648486647511119341978)
'''

exp:

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from hashlib import md5

def MD5(m):return md5(str(m).encode()).hexdigest()
p=11093300438765357787693823122068501933326829181518693650897090781749379503427651954028543076247583697669597230934286751428880673539155279232304301123931419
a=490963434153515882934487973185142842357175523008183292296815140698999054658777820556076794490414610737654365807063916602037816955706321036900113929329671
b=7668542654793784988436499086739239442915170287346121645884096222948338279165302213440060079141960679678526016348025029558335977042712382611197995002316466
G=(4045939664332192284605924284905750194599514115248885617006435833400516258314135019849306107002566248677228498859069119557284134574413164612914441502516162, 2847794627838984866808853730797794758944159239755903652092146137932959816137006954045318821531984715562135134681256836794735388745354065994745661832926404)
K=(9857925495630886472871072848615069766635115253576843197716242339068269151167072057478472997523547299286363591371734837904400286993818976404285783613138603, 9981865329938877904579306200429599690480093951555010258809210740458120586507638100468722807717390033784290215217185921690103757911870933497240578867679716)
C1=(4349662787973529188741615503085571493571434812105745603868205005885464592782536198234863020839759214118594741734453731681116610298272107088387481605173124, 10835708302355425798729392993451337162773253000440566333611610633234929294159743316615308778168947697567386109223430056006489876900001115634567822674333770)
C2=(5193866657417498376737132473732737330916570240569047910293144235752602489388092937375844109374780050061859498276712695321973801207620914447727053101524592, 684299154840371832195648774293174908478389728255128448106858267664482339440737099810868633906297465450436417091302739473407943955874648486647511119341978)

E = EllipticCurve(GF(p), [0, 0, 0, a, b])
P = E([K[0],K[1]])
Q = E([G[0],G[1]])
c1 = E([C1[0],C1[1]])
c2 = E([C2[0],C2[1]])

def SmartAttack(P,Q,p):
E = P.curve()
Eqp = EllipticCurve(Qp(p, 2), [ ZZ(t) + randint(0,p)*p for t in E.a_invariants() ])

P_Qps = Eqp.lift_x(ZZ(P.xy()[0]), all=True)
for P_Qp in P_Qps:
if GF(p)(P_Qp.xy()[1]) == P.xy()[1]:
break

Q_Qps = Eqp.lift_x(ZZ(Q.xy()[0]), all=True)
for Q_Qp in Q_Qps:
if GF(p)(Q_Qp.xy()[1]) == Q.xy()[1]:
break

p_times_P = p*P_Qp
p_times_Q = p*Q_Qp

x_P,y_P = p_times_P.xy()
x_Q,y_Q = p_times_Q.xy()

phi_P = -(x_P/y_P)
phi_Q = -(x_Q/y_Q)
k = phi_Q/phi_P
return ZZ(k)

r = SmartAttack(P, Q, p)
print(MD5((c1-k*c2).xy()[0]))

Drange Leak

下载附件

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from random import *
from secret import flag
from Crypto.Util.number import *

m = bytes_to_long(flag)
p = getPrime(1024)
q = getPrime(1024)
n = p * q
phi = (p - 1) * (q - 1)
while True:
M = getrandbits(954)
d0 = getrandbits(70)
d1 = getrandbits(60)
d = M * d1 + d0
e = inverse(d, (p - 1) * (q - 1))
if GCD(d,phi) == 1:
break


c = pow(m,e,n)
print(f'n = {n}')
print(f'e = {e}', )
print(f'c = {c}')
print(f'leak={M}')

'''
n = 20890649807098098590988367504589884104169882461137822700915421138825243082401073285651688396365119177048314378342335630003758801918471770067256781032441408755600222443136442802834673033726750262792591713729454359321085776245901507024843351032181392621160709321235730377105858928038429561563451212831555362084799868396816620900530821649927143675042508754145300235707164480595867159183020730488244523890377494200551982732673420463610420046405496222143863293721127847196315699011480407859245602878759192763358027712666490436877309958694930300881154144262012786388678170041827603485103596258722151867033618346180314221757
e = 18495624691004329345494739768139119654869294781001439503228375675656780205533832088551925603457913375965236666248560110824522816405784593622489392063569693980307711273262046178522155150057918004670062638133229511441378857067441808814663979656329118576174389773223672078570346056569568769586136333878585184495900769610485682523713035338815180355226296627023856218662677851691200400870086661825318662718172322697239597148304400050201201957491047654347222946693457784950694119128957010938708457194638164370689969395914866589468077447411160531995194740413950928085824985317114393591961698215667749937880023984967171867149
c = 7268748311489430996649583334296342239120976535969890151640528281264037345919563247744198340847622671332165540273927079037288463501586895675652397791211130033797562320858177249657627485568147343368981852295435358970875375601525013288259717232106253656041724174637307915021524904526849025976062174351360431089505898256673035060020871892556020429754849084448428394307414301376699983203262072041951835713075509402291301281337658567437075609144913905526625759374465018684092236818174282777215336979886495053619105951835282087487201593981164477120073864259644978940192351781270609702595767362731320959397657161384681459323
leak=136607909840146555806361156873618892240715868885574369629522914036807393164542930308166609104735002945881388216362007941213298888307579692272865700211608126496105057113506756857793463197250909161173116422723246662094695586716106972298428164926993995948528941241037242367190042120886133717
'''

exp:

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import itertools
from Crypto.Util.number import *

def small_roots(f, bounds, m=1, d=None):
if not d:
d = f.degree()

R = f.base_ring()
N = R.cardinality()

f /= f.coefficients().pop(0)
f = f.change_ring(ZZ)

G = Sequence([], f.parent())
for i in range(m+1):
base = N^(m-i) * f^i
for shifts in itertools.product(range(d), repeat=f.nvariables()):
g = base * prod(map(power, f.variables(), shifts))
G.append(g)

B, monomials = G.coefficient_matrix()
monomials = vector(monomials)

factors = [monomial(*bounds) for monomial in monomials]
for i, factor in enumerate(factors):
B.rescale_col(i, factor)

B = B.dense_matrix().LLL()

B = B.change_ring(QQ)
for i, factor in enumerate(factors):
B.rescale_col(i, 1/factor)

H = Sequence([], f.parent().change_ring(QQ))
for h in filter(None, B*monomials):
H.append(h)
I = H.ideal()
if I.dimension() == -1:
H.pop()
elif I.dimension() == 0:
roots = []
for root in I.variety(ring=ZZ):
root = tuple(R(root[var]) for var in f.variables())
roots.append(root)
return roots
return []

n = 20890649807098098590988367504589884104169882461137822700915421138825243082401073285651688396365119177048314378342335630003758801918471770067256781032441408755600222443136442802834673033726750262792591713729454359321085776245901507024843351032181392621160709321235730377105858928038429561563451212831555362084799868396816620900530821649927143675042508754145300235707164480595867159183020730488244523890377494200551982732673420463610420046405496222143863293721127847196315699011480407859245602878759192763358027712666490436877309958694930300881154144262012786388678170041827603485103596258722151867033618346180314221757
e = 18495624691004329345494739768139119654869294781001439503228375675656780205533832088551925603457913375965236666248560110824522816405784593622489392063569693980307711273262046178522155150057918004670062638133229511441378857067441808814663979656329118576174389773223672078570346056569568769586136333878585184495900769610485682523713035338815180355226296627023856218662677851691200400870086661825318662718172322697239597148304400050201201957491047654347222946693457784950694119128957010938708457194638164370689969395914866589468077447411160531995194740413950928085824985317114393591961698215667749937880023984967171867149
c = 7268748311489430996649583334296342239120976535969890151640528281264037345919563247744198340847622671332165540273927079037288463501586895675652397791211130033797562320858177249657627485568147343368981852295435358970875375601525013288259717232106253656041724174637307915021524904526849025976062174351360431089505898256673035060020871892556020429754849084448428394307414301376699983203262072041951835713075509402291301281337658567437075609144913905526625759374465018684092236818174282777215336979886495053619105951835282087487201593981164477120073864259644978940192351781270609702595767362731320959397657161384681459323
leak=136607909840146555806361156873618892240715868885574369629522914036807393164542930308166609104735002945881388216362007941213298888307579692272865700211608126496105057113506756857793463197250909161173116422723246662094695586716106972298428164926993995948528941241037242367190042120886133717
PR.<x,k,z> = PolynomialRing(Zmod(e*leak))
f = e*x - k*n + k*z - 1
roots = small_roots(f,(2^100,2^1024,2^1024),3,3)
print(roots)
#从这里得到的z = (p+q-1),后续直接解方程就可以了。

LLL-ThirdBlood

exp1:

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#part1:拖取数据
from pwn import *
from hashlib import sha1
from Crypto.Util.number import *

context(os='linux', arch='amd64', log_level='debug')
h = bytes_to_long(sha1(b'test').digest())
s = []
r = []

io = remote('0.0.0.0',10002)

def Sign(target):
target.sendafter(b'>',b'S')
target.sendafter(b'>',b'test')
target.recvuntil(b's = ')
s_ = int(target.recvline())
target.recvuntil(b'r = ')
r_ = int(target.recvline())
s.append(s_)
r.append(r_)

io.recvuntil(b'q=')
q=int(io.recvline())
io.recvuntil(b'g=')
g=int(io.recvline())
io.recvuntil(b'y=')
y=int(io.recvline())

for i in range(10):
Sign(io)
io.close()

print(f'q={q}')
print(f'h={h}')
print(f'r={r}')
print(f's={s}')

exp2:

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from Crypto.Util.number import inverse
q=
h=
r=
s=
#填入以上数据

A=[]
B=[]
M=[]

t = 120
#填入k的大概位数,相当于一个上界,比想要求解的向量大一点就行
for i in range(len(r)):
tmp = [0 for i in range(len(r)+2)]
tmp[i] = q
A.append(mod(r[i]*s[0]*inverse_mod(r[0]*s[i],q),q))
B.append(mod((r[0]*h-r[i]*h)*inverse_mod(r[0]*s[i],q),q))
M.append(tmp)

A.extend([1,0])
B.extend([0,2^(t)])
M.append(A)
M.append(B)
M = matrix(ZZ, M)
#构造矩阵
T = M.LLL()

s0 = s[0]
s1 = s[1]
r0 =r[0]
k = T[0][0]
x = inverse(r0, q) * (s0 * k - h) % q
print(x)
#获得私钥

exp3:

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from Crypto.Util.number import *
from random import getrandbits,randint
from hashlib import sha1
pri_key = 27462250581507679486

class DSA:
def __init__(self):
self.q=
self.p=
self.g=
self.y=
self.x = pri_key
def sign(self,m):
H = bytes_to_long(sha1(m).digest())
k = getrandbits(128)
r = pow(self.g,k,self.p)%self.q
s = (inverse(k,self.q)*(H+r*self.x))%self.q
return (s,r)

def verify(self,m,s_,r_):
H = bytes_to_long(sha1(m).digest())
u1 = (inverse(s_,self.q)*H)%self.q
u2 = (inverse(s_,self.q)*r_)%self.q
r = (pow(self.g,u1,self.p)*pow(self.y,u2,self.p))%self.p%self.q
if r == r_:
return True
else:
return False

Test = DSA()
s,r = Test.sign(b'admin')
assert Test.verify(b'admin',s,r) == True
print(s,r)

文章作者: yiqing
版权声明: 本博客所有文章除特別声明外,均采用 CC BY 4.0 许可协议。转载请注明来源 yiqing !
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